1. For the CMOS inverter, with Vin = 0V, the drain current of the “ON” MOSFET is 10mA and VDS = 0.25V. What is the value of the resistance of the circuit ?
a) 8 V
b) 8.05 V
c) 7.65 V
d) 8.0275 V
3. X = 101101, Y = 101011 Initially JK Flip Flop is reset. Find the output.
a) Mod-14 counter
b) Mod-10 counter
c) 4-bit shift counter
d) 16-bit shift counter
a) V’Qn’ + U’Qn
b) VQn’ + U’Qn
b) Pulse position modulator
c) Pulse width modulator
d) Astable multivibrator
8. The step size of a 10-bit DAC is 25mV. What will be the value of full scale output voltage ?
a) 27.53 V
b) 23.57 V
c) 22 V
d) 25.57 V
9. For a full wave rectifier, if the Root mean square value of the voltage is increased by four times then;
a) Peak amplitude of the source voltage increases 4 times
b) Peak amplitude of the source voltage increases 1/4 times
c) Peak amplitude of the source voltage decreases 4 times
d) Peak amplitude of the source voltage increases 1/4 times
10. Four inputs of 4:1 mux are 0 A A 1 respectively select lines are B C what is expression implemented using this mux ?
a) AB +BC + AC
b) A + BC
c) AB + AC
11. In terms of structure, differentiate the microprocessor with respect to microcontrollers:
a) Microcontroller is a part of microprocessor
b) Function of Microcontroller & microprocessor is totally different
c) Microprocessor is a part or unit of Microcontroller
d) Function of the Microcontroller & microprocessor is same for a same device
12. An N-bit parallel counter has input frequency of 64kHz and output frequency of 4kHz, what is the value of N.
a) 16
b) 4
c) 8
d) 60
13. A semiconductor has the following parameters
Conductivity is minimum when the hole concentration is:
a) 68 X 1011 / cm3
b) 6.8 X 1015 / cm3
c) 9.8 X 1019 / cm3
d) 6.8 X 1021 / cm314. According to Microprocessor architecture, how many steps are use in execution Model and what they are ? And what is the sequence ?
a) 2,reads and interprets
b) 3, reads, interprets and execute
c) 3, reads, execute and interprets
d) 3, execute, reads and interprets
15. Calculate the value of band gap energy of a semiconductor having wavelength of 500nm.
a) 1.28 eV
b) 2.48 eV
c) 2.98 eV
d) 3.20 eV
b) 64 K words
c) 256 K words
d) 256 K bytes
a) Hartley Oscillator, f = 1/2Ï€√(L1 x C1 x C2)
b) Colpitt’s Oscillator, f = 1/2Ï€√(L1 x C) where C = ( C1 x C2) / (C1 + C2)
c) RC Phase shift Oscillator f = 1/2Ï€√(L x C)
d) Crystal Oscillator f = 1/2Ï€√(L x C)
#include<stdio.h>
int main()
{
int skip[][3] = {15,17,19};
while(!0)
{
printf("%d",*(skip + 2) - 1);
}
return 0;
#include<stdio.h>
int main()
{
int j = 2,k = 4;
printf(&j["Programming"], &k["Theory"]);
k = j ^ 3;
if (k == j)
printf(&k["Practical"], "Trytosolve");
else
printf(&j["Problem creation"]);
return 0;
}
a) ProTheocal
b) grammingblem
c) ogrammingoblem creation
d) ryctical
#include<stdio.h>
int main()
{
unsigned int f = 4,i;
for(i = 0; i<2; i++)
{
f <<= ++i ^ f - 1;
if (f > 2)
printf("%d ",f ^ 1);
else
printf("%d ", f & 1);
}
return 0
}
b) 17
c) 10
d) 0
#include<stdio.h>
int main()
{
switch(2.5) // statement 1
{
case 2.5f : printf("abcd"); // statement 2
break;
case 2.5 : printf("efgh"); // statement 3
break;
case 2 : printf("pqrs");
break;
default : printf("mnop");
}
return 0;
}
a) Statement 2 and Statement 3
b) Statement 1
c) All Statement 1, Statement 2 and Statement 3
d) No error in the program
a) A = 1 B = 0
b) A = 0 B = 0
c) A = 1 B = 1
d) None of the given options
24. What will be the output of the program given below ?
#include<stdio.h>
#define sizeof(int) 3
#define float int
int main()
{
float a;
if(a = sizeof(int) / sizeof(float))
if(a == 1.000000)
printf("Testing");
printf("OK");
return 0;
}
a) OKTesting
b) OK
c) Testing
d) TestingOK
a) FCFS scheduling algorithm
b) Lottery scheduling algorithm
c) RR scheduling algorithm
d) LRU scheduling algorithm
I) When both inputs are ‘1’, the output of this gate is always ‘1’,
II) It is a modulo two adder gate.
a) Only(I)
b) Only(II)
c) Both (I) and (II)
d) Neither (I) nor (II)
27. Find the equivalent octal number for the given decimal number.
(120.25)10
q) 170.2
b) 125.5
c) 192.2
28. The elements given below are sorted in ascending order using quick sort. First elements of the list is always chosen as Pivot.
22 81 91 31 10 38 75 69
a) 81
b) 38
c) 91
d) 10
29. How many bits will be present in the physical address if there are 8 segments present in the memory system each having a size of 2KB ?
a) 9 bits
b) 14 bits
c) 11 bits
d) 12 bits
30. Which one of the given options is the correct result for two’s complements addition of the binary numbers given below ?
10011011 + 11011001 = ?
a) 01110100 with carry
b) 11011011 without carry
c) 11011011 with carry
d) 01110100 without carry
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